GCEMathematicsIndices, Logarithms and Surds2019

(a) Solve for x in the equation: 3^(2x+1) - 26(3^x) - 9 = 0. [6 marks] (b) Given that log(base 2)(y + 3) + log(base 2)(y - 3) = log(base 2)(7y - 3), find the value of y. [5 marks] (c) Simplify: (sqrt(5) + sqrt(3))^2 - (sqrt(5) - sqrt(3))^2, leaving your answer in the form k*sqrt(n), where k and n are integers. [4 marks]

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