Find the equation of the line that passes through the point (1, 2) and is parallel to the line $3x - 2y + 5 = 0$.

Parallel lines have the same gradient. From 3x − 2y + 5 = 0, gradient m = 3/2. Using point (1, 2): y − 2 = (3/2)(x − 1), so 2y − 4 = 3x − 3, giving 3x − 2y − 1 = 0. Option A has the wrong constant, option C uses the perpendicular gradient, and option D changes the sign of the y-coefficient.