Factorize completely: $2x^2 - 8x$
A$2(x^2 - 4x)$
B$2x(x - 4)$CORRECT
C$x(2x - 8)$
D$2(x^2 - 8)$
GCEMathematicsAlgebraic Processes2019
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Why the answer is B, and why the others tempt you.
The HCF of 2x² and 8x is 2x. Dividing each term by 2x gives: 2x(x - 4). While options A and C are partially factorized, only option B is completely factorized with the HCF taken out fully.
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