If $\log_x 64 = 3$, find the value of $x$.

$\log_x 64 = 3$ means $x^3 = 64$, so $x = \sqrt[3]{64} = 4$. Candidates who confuse the base and the argument may choose 8 (since $8^2 = 64$) or 2 (since $2^6 = 64$).