Simplify $\frac{\sqrt{3}}{\sqrt{3} - 1}$, rationalising the denominator.

Question

Accepted Answer

$\frac{3 + \sqrt{3}}{2}$. Multiply numerator and denominator by the conjugate $(\sqrt{3} + 1)$: numerator becomes $\sqrt{3}(\sqrt{3} + 1) = 3 + \sqrt{3}$, denominator becomes $(\sqrt{3})^2 - 1^2 = 3 - 1 = 2$. The result is $\frac{3 + \sqrt{3}}{2}$.

Answer

A) $\frac{3 + \sqrt{3}}{2}$

Answer

B) $\frac{3 - \sqrt{3}}{2}$

Answer

C) $\frac{\sqrt{3} + 1}{2}$

Answer

D) $3 + \sqrt{3}$

Simplify $\frac{\sqrt{3}}{\sqrt{3} - 1}$, rationalising the denominator.

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