GCEMathematicsIndices, Logarithms and Surds2020

Evaluate $3^{-2} \times 27^{\frac{2}{3}}$

A1CORRECT
B3
C9
D$\frac{1}{3}$
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Why the answer is A, and why the others tempt you.
$3^{-2} = \frac{1}{9}$ and $27^{\frac{2}{3}} = (3^3)^{\frac{2}{3}} = 3^2 = 9$. Multiplying gives $\frac{1}{9} \times 9 = 1$. Distractors arise from sign errors or misapplication of the fractional exponent.
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