What is the sum of the interior angles of a pentagon?
A540°CORRECT
B360°
C720°
D450°
Common EntranceMathematicsAngles
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Why the answer is A, and why the others tempt you.
Sum of interior angles = (n - 2) x 180°. For a pentagon n = 5, so (5 - 2) x 180° = 540°.
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