When ethyne is bubbled through excess bromine, the final product is
A1,2-dibromoethane
Bbromoethane
C1,1,2,2-tetrabromoethaneCORRECT
D1,2-dibromoethene
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Why the answer is C, and why the others tempt you.
The triple bond can add two molecules of bromine in succession: first to 1,2-dibromoethene, then, with excess bromine, to 1,1,2,2-tetrabromoethane, CHBr$_2$CHBr$_2$. 1,2-dibromoethane is the product from ethene, which has only one double bond to add across.
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