The hybridisation of each carbon atom in ethyne, HC≡CH, is
AspCORRECT
Bsp$^3$
Csp$^2$
Dsp$^3$d
JUPEBChemistryOrganic Chemistry: Hydrocarbons
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Why the answer is A, and why the others tempt you.
Each carbon in ethyne forms two sigma bonds (one to H, one to C) and two pi bonds, requiring only two hybrid orbitals, so it is sp hybridised and the molecule is linear. Ethene carbons are sp$^2$ and ethane carbons are sp$^3$.
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