50 cm$^3$ of a 2.0 mol dm$^{-3}$ solution is diluted with water to 500 cm$^3$. What is the new concentration?

Question

Accepted Answer

0.2 mol dm$^{-3}$. Moles are unchanged on dilution: $C_1V_1 = C_2V_2$, so $C_2 = \dfrac{2.0 	imes 50}{500} = 0.2$ mol dm$^{-3}$. Inverting the volume ratio gives 20.

Answer

A) 20 mol dm$^{-3}$

Answer

B) 0.2 mol dm$^{-3}$

Answer

C) 0.02 mol dm$^{-3}$

Answer

D) 1.0 mol dm$^{-3}$

50 cm$^3$ of a 2.0 mol dm$^{-3}$ solution is diluted with water to 500 cm$^3$. What is the new concentration?

Practice more Chemistry questions