JUPEBChemistryStoichiometry and Volumetric Analysis

How many molecules are present in 0.5 mol of carbon dioxide? (Avogadro's constant $= 6.02 \times 10^{23}$ mol$^{-1}$)

A$3.01 \times 10^{23}$CORRECT
B$6.02 \times 10^{23}$
C$3.01 \times 10^{22}$
D$1.204 \times 10^{24}$
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Why the answer is A, and why the others tempt you.
Number of molecules $= 0.5 \times 6.02 \times 10^{23} = 3.01 \times 10^{23}$. Dividing by 0.5 gives $1.204 \times 10^{24}$.
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