Calculate the percentage by mass of nitrogen in ammonium nitrate, NH$_4$NO$_3$. (N = 14, H = 1, O = 16)
A35%CORRECT
B17.5%
C28%
D70%
JUPEBChemistryStoichiometry and Volumetric Analysis
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Why the answer is A, and why the others tempt you.
Molar mass $= 14 + 4 + 14 + 48 = 80$. Nitrogen present $= 2 \times 14 = 28$, so percentage $= \dfrac{28}{80} \times 100 = 35\%$. Counting only one nitrogen atom gives 17.5%.
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