Calculate the molar mass of calcium carbonate, CaCO$_3$. (Ca = 40, C = 12, O = 16)
A84 g mol$^{-1}$
B116 g mol$^{-1}$
C100 g mol$^{-1}$CORRECT
D68 g mol$^{-1}$
JUPEBChemistryStoichiometry and Volumetric Analysis
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Why the answer is C, and why the others tempt you.
$40 + 12 + (3 \times 16) = 40 + 12 + 48 = 100$ g mol$^{-1}$. Counting only one oxygen gives 68.
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