In a balanced Wheatstone bridge, the resistances in three arms are $2\ \Omega$, $4\ \Omega$ and $3\ \Omega$, arranged so that $\dfrac{2}{4} = \dfrac{3}{X}$. Find the unknown resistance $X$.

Question

Accepted Answer

$6\ \Omega$. At balance $\dfrac{R_1}{R_2} = \dfrac{R_3}{R_4}$, so $\dfrac{2}{4} = \dfrac{3}{X}$ gives $2X = 12$ and $X = 6\ \Omega$. Inverting one ratio gives 1.5.

Answer

A) $0.67\ \Omega$

Answer

B) $1.5\ \Omega$

Answer

C) $24\ \Omega$

Answer

D) $6\ \Omega$

In a balanced Wheatstone bridge, the resistances in three arms are $2\ \Omega$, $4\ \Omega$ and $3\ \Omega$, arranged so that $\dfrac{2}{4} = \dfrac{3}{X}$. Find the unknown resistance $X$.

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