A $1500$ W electric kettle is used for $2$ hours. Calculate the electrical energy consumed, in joules.
A$1.08 \times 10^7$ JCORRECT
B$3$ J
C$3000$ J
D$10800$ J
JUPEBPhysicsCurrent Electricity
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Toaster Teacher
Why the answer is A, and why the others tempt you.
$E = Pt = 1500 \times (2 \times 3600) = 1500 \times 7200 = 1.08 \times 10^7$ J, which is 3 kWh. Failing to convert hours to seconds gives 3000.
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