A $6\ \Omega$ resistor and a $3\ \Omega$ resistor are connected in parallel. Find the combined resistance.
A$4.5\ \Omega$
B$9\ \Omega$
C$2\ \Omega$CORRECT
D$0.5\ \Omega$
JUPEBPhysicsCurrent Electricity
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Why the answer is C, and why the others tempt you.
$\dfrac{1}{R} = \dfrac{1}{6} + \dfrac{1}{3} = \dfrac{1}{6} + \dfrac{2}{6} = \dfrac{3}{6}$, so $R = 2\ \Omega$. Stopping at $\dfrac{1}{R} = 0.5$ and reporting 0.5 is the common error; the parallel value must be less than the smaller resistor.
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