Three resistors of $2\ \Omega$, $3\ \Omega$ and $5\ \Omega$ are connected in series. Find the total resistance.
A$10\ \Omega$CORRECT
B$30\ \Omega$
C$0.97\ \Omega$
D$1.03\ \Omega$
JUPEBPhysicsCurrent Electricity
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Why the answer is A, and why the others tempt you.
In series, resistances add: $2 + 3 + 5 = 10\ \Omega$. The value 0.97 is the parallel combination.
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