A $4\ \Omega$ resistor is connected across a $12$ V battery of negligible internal resistance. Find the current.
A$8$ A
B$3$ ACORRECT
C$0.33$ A
D$48$ A
JUPEBPhysicsCurrent Electricity
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Why the answer is B, and why the others tempt you.
From Ohm's law, $I = \dfrac{V}{R} = \dfrac{12}{4} = 3$ A. Multiplying gives 48 and inverting gives 0.33.
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