A $0.5$ kg mass hangs from a spring of force constant $200$ N m$^{-1}$. Find the period of its vertical oscillations.

Question

Accepted Answer

$\dfrac{\pi}{10}$ s. $T = 2\pi\sqrt{\dfrac{m}{k}} = 2\pi\sqrt{\dfrac{0.5}{200}} = 2\pi\sqrt{0.0025} = 2\pi 	imes 0.05 = \dfrac{\pi}{10}$ s (about 0.31 s). Inverting $m/k$ under the root gives $40\pi$.

Answer

A) $40\pi$ s

Answer

B) $\dfrac{\pi}{10}$ s

Answer

C) $\dfrac{\pi}{5}$ s

Answer

D) $10\pi$ s

A $0.5$ kg mass hangs from a spring of force constant $200$ N m$^{-1}$. Find the period of its vertical oscillations.

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