A spring of force constant $200$ N m$^{-1}$ is compressed by $10$ cm. Calculate the elastic potential energy stored.
A$1$ JCORRECT
B$1000$ J
C$2$ J
D$10$ J
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Why the answer is A, and why the others tempt you.
$E = \dfrac{1}{2}kx^2 = \dfrac{1}{2} \times 200 \times (0.1)^2 = 100 \times 0.01 = 1$ J. Leaving $x$ in centimetres gives 1000 J, and forgetting the half gives 2 J.
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