A body moving at $20$ m s$^{-1}$ is brought uniformly to rest in $4$ s. Calculate the distance it covers while decelerating.
A$5$ m
B$40$ mCORRECT
C$160$ m
D$80$ m
JUPEBPhysicsKinematics and Dynamics
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Why the answer is B, and why the others tempt you.
Distance is the average velocity multiplied by time: $\dfrac{20 + 0}{2} \times 4 = 40$ m. Using the initial velocity alone, $20 \times 4 = 80$ m, ignores the deceleration.
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