Solve $2\sin x - 1 = 0$ for $0^\circ \le x \le 360^\circ$.

Question

Accepted Answer

$x = 30^\circ$ or $150^\circ$. $\sin x = \dfrac{1}{2}$, so the principal value is $30^\circ$. Sine is also positive in the second quadrant, giving $180^\circ - 30^\circ = 150^\circ$. The value $210^\circ$ would need sine to be negative, and $60^\circ$ corresponds to $\sin x = \dfrac{\sqrt{3}}{2}$.

Answer

A) $x = 30^\circ$ or $210^\circ$

Answer

B) $x = 30^\circ$ only

Answer

C) $x = 60^\circ$ or $120^\circ$

Answer

D) $x = 30^\circ$ or $150^\circ$

Solve $2\sin x - 1 = 0$ for $0^\circ \le x \le 360^\circ$.

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