Evaluate $27^{\frac{2}{3}} imes 9^{-\frac{1}{2}}$.

Question

Evaluate $27^{\frac{2}{3}} 	imes 9^{-\frac{1}{2}}$.

Accepted Answer

$3$. $27^{\frac{2}{3}} = (3^3)^{\frac{2}{3}} = 3^2 = 9$ and $9^{-\frac{1}{2}} = \dfrac{1}{\sqrt{9}} = \dfrac{1}{3}$. The product is $9 	imes \dfrac{1}{3} = 3$. Treating the negative index as making the whole answer a fraction gives $\dfrac{1}{3}$.

Answer

A) $9$

Answer

B) $27$

Answer

C) $\dfrac{1}{3}$

Answer

D) $3$

Evaluate $27^{\frac{2}{3}} \times 9^{-\frac{1}{2}}$.

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