Rationalise the denominator of $\dfrac{3}{2 - \sqrt{3}}$.

Question

Accepted Answer

$6 + 3\sqrt{3}$. Multiply numerator and denominator by the conjugate $2 + \sqrt{3}$. The denominator becomes $(2)^2 - (\sqrt{3})^2 = 4 - 3 = 1$, and the numerator becomes $3(2 + \sqrt{3}) = 6 + 3\sqrt{3}$. Dividing by 7 comes from wrongly adding 4 and 3 in the denominator.

Answer

A) $6 + 3\sqrt{3}$

Answer

B) $6 - 3\sqrt{3}$

Answer

C) $\dfrac{6 + 3\sqrt{3}}{7}$

Answer

D) $2 + \sqrt{3}$

Rationalise the denominator of $\dfrac{3}{2 - \sqrt{3}}$.

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