A student is to answer 8 out of 12 questions in an examination. In how many ways can the student make the selection if questions 1 and 2 must both be answered?

Since questions 1 and 2 must both be answered, the student needs to choose 6 more from the remaining 10 questions. The number of ways = C(10,6) = 10!/(6! × 4!) = 210. Option C gives C(12,8) = 495, which ignores the constraint.