How many ways can a committee of 3 be chosen from 8 people?
A24
B56CORRECT
C112
D336
GCEFurther MathematicsPermutations and Combinations2020
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Why the answer is B, and why the others tempt you.
This is a combination problem since order does not matter. C(8,3) = 8!/(3! × 5!) = (8 × 7 × 6)/(3 × 2 × 1) = 336/6 = 56. Option D (336) is the permutation P(8,3), a common error.
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