Evaluate $\int_{0}^{2} (x^2 + 1)\, dx$

Question

Accepted Answer

$\frac{14}{3}$. Integrating gives [x³/3 + x] evaluated from 0 to 2. At x = 2: 8/3 + 2 = 8/3 + 6/3 = 14/3. At x = 0: 0. The result is 14/3. Option D arises from forgetting the +1 term's contribution correctly.

Answer

A) 5

Answer

B) 4

Answer

C) $\frac{14}{3}$

Answer

D) $\frac{10}{3}$

Evaluate $\int_{0}^{2} (x^2 + 1)\, dx$

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