If $\sin heta = \frac{5}{13}$ and $ heta$ is acute, find the value of $ an heta$.

Question

If $\sin	heta = \frac{5}{13}$ and $	heta$ is acute, find the value of $	an	heta$.

Accepted Answer

$\frac{5}{12}$. Using a 5-12-13 right triangle: sin θ = 5/13 means opposite = 5, hypotenuse = 13, so adjacent = 12. Therefore tan θ = opposite/adjacent = 5/12. Option D is the reciprocal, a common error.

Answer

A) $\frac{5}{12}$

Answer

B) $\frac{12}{13}$

Answer

C) $\frac{13}{12}$

Answer

D) $\frac{12}{5}$

If $\sin\theta = \frac{5}{13}$ and $\theta$ is acute, find the value of $\tan\theta$.

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