The sum of the first n terms of a series is given by $S_n = 3n^2 + 2n$. Find the 5th term of the series.

The nth term is found by T_n = S_n - S_(n-1). S_5 = 3(25) + 2(5) = 75 + 10 = 85. S_4 = 3(16) + 2(4) = 48 + 8 = 56. So T_5 = 85 - 56 = 29. Rechecking: T_n = S_n - S_(n-1) = 3n²+2n - [3(n-1)²+2(n-1)] = 3(2n-1)+2 = 6n-1. T_5 = 30-1 = 29. The closest option is A=32 but the exact answer is 29; using the formula T_n=6n-1 gives T_5=29. Option B (85) is S_5 itself, a common error.