What volume of oxygen (measured at s.t.p.) is required for the complete combustion of 2.0 dm³ of propane gas at s.t.p.? [C₃H₈ + 5O₂ → 3CO₂ + 4H₂O]
A5.0 dm³
B10.0 dm³CORRECT
C15.0 dm³
D2.5 dm³
GCEChemistryOrganic Chemistry2020
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Why the answer is B, and why the others tempt you.
From the equation, 1 mole of propane requires 5 moles of oxygen. By Gay-Lussac's law, volumes are in the same ratio at the same temperature and pressure. Therefore 2.0 dm³ of propane requires 2.0 × 5 = 10.0 dm³ of oxygen.
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