Given that the activation energy of a reaction is 80 kJ mol⁻¹ and a catalyst lowers it to 50 kJ mol⁻¹, what is the reduction in activation energy?

Question

Accepted Answer

30 kJ mol⁻¹. The reduction in activation energy = 80 − 50 = 30 kJ mol⁻¹. Option A is the sum of both values, option C is the catalysed activation energy, and option D is the uncatalysed activation energy — all common errors.

Answer

A) 130 kJ mol⁻¹

Answer

B) 30 kJ mol⁻¹

Answer

C) 50 kJ mol⁻¹

Answer

D) 80 kJ mol⁻¹

Given that the activation energy of a reaction is 80 kJ mol⁻¹ and a catalyst lowers it to 50 kJ mol⁻¹, what is the reduction in activation energy?

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