25.0 cm³ of 0.10 mol dm⁻³ sodium hydroxide solution is exactly neutralised by 12.5 cm³ of a sulphuric acid solution. What is the concentration of the sulphuric acid?

Question

Accepted Answer

0.10 mol dm⁻³. Moles of NaOH = 0.025 × 0.10 = 0.0025 mol. The equation is H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O, so moles of H₂SO₄ = 0.0025 ÷ 2 = 0.00125 mol. Concentration of H₂SO₄ = 0.00125 ÷ 0.0125 = 0.10 mol dm⁻³.

Answer

A) 0.025 mol dm⁻³

Answer

B) 0.050 mol dm⁻³

Answer

C) 0.10 mol dm⁻³

Answer

D) 0.20 mol dm⁻³

25.0 cm³ of 0.10 mol dm⁻³ sodium hydroxide solution is exactly neutralised by 12.5 cm³ of a sulphuric acid solution. What is the concentration of the sulphuric acid?

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