At s.t.p., what volume is occupied by 0.50 mol of carbon(IV) oxide gas?
A5.6 dm³
B11.2 dm³CORRECT
C22.4 dm³
D44.8 dm³
GCEChemistryStoichiometry and Mole Concept2024
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Why the answer is B, and why the others tempt you.
At s.t.p., one mole of any ideal gas occupies 22.4 dm³. Therefore 0.50 mol occupies 0.50 × 22.4 = 11.2 dm³. Option C is the molar volume (1 mol), option A corresponds to 0.25 mol, and option D corresponds to 2 mol.
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