What is the mass of 0.25 mol of trioxonitrate(V) acid, HNO₃? [H = 1, N = 14, O = 16]
A7.875 g
B15.75 gCORRECT
C31.50 g
D63.00 g
GCEChemistryStoichiometry and Mole Concept2023
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Why the answer is B, and why the others tempt you.
The molar mass of HNO₃ = 1 + 14 + (3 × 16) = 63 g/mol. Mass = moles × molar mass = 0.25 × 63 = 15.75 g. Option D is the molar mass itself (1 mol), option C corresponds to 0.5 mol, and option A is a common arithmetic slip.
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