The bond angle in a molecule of BF₃ is
A90°
B104.5°
C107°
D120°CORRECT
GCEChemistryChemical Bonding2020
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Why the answer is D, and why the others tempt you.
BF₃ has three bonding pairs and no lone pairs around the central boron atom, giving it a trigonal planar geometry according to VSEPR theory. This geometry corresponds to bond angles of exactly 120°. The absence of lone pairs means there is no distortion of the ideal angle.
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