A converging lens of focal length 20 cm is used as a magnifying glass. If the image is formed at the near point (25 cm) from the eye, what is the magnification produced?

The magnification of a simple magnifying glass when the image is at the near point D is given by $m = 1 + \frac{D}{f}$, where D = 25 cm and f = 20 cm. Thus $m = 1 + \frac{25}{20} = 1 + 1.25 = 2.25$. Distractor A represents only D/f, while C and D are common arithmetic errors.