A ray of light travels from glass of refractive index 1.5 into air. What is the critical angle for the glass-air interface?
A19.5°
B41.8°CORRECT
C48.2°
D56.4°
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Why the answer is B, and why the others tempt you.
The critical angle C is given by sin C = 1/n, where n is the refractive index of glass. sin C = 1/1.5 = 0.6667, so C = sin⁻¹(0.6667) ≈ 41.8°. At angles of incidence greater than this, total internal reflection occurs.
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