A satellite orbits the Earth at a height where the gravitational acceleration is 8 m/s². If the radius of the orbit is 6.7 × 10⁶ m, what is the orbital speed of the satellite?

For a satellite in circular orbit, gravitational force provides centripetal force: mg = mv²/r, so v² = gr = 8 × 6.7 × 10⁶ = 5.36 × 10⁷. Therefore v = √(5.36 × 10⁷) ≈ 7321 m/s. Option C incorrectly uses v = gr directly, while option A results from an arithmetic error in computing the square root.