A body of mass 2 kg is suspended by two strings making angles of 30° and 60° with the vertical respectively. If the system is in equilibrium, what is the tension in the string making 30° with the vertical? [g = 10 m/s²]

For equilibrium, the horizontal components give T₁sin30° = T₂sin60°, and the vertical components give T₁cos30° + T₂cos60° = mg = 20 N. Solving simultaneously: T₁(√3/2) + T₁(sin30°/sin60°)(1/2) = 20, which simplifies to T₁(√3/2 + 1/(2√3)) = 20, giving T₁(4/(2√3)) = 20 and T₁ = 10√3/√3... Resolving correctly yields T₁ = 10 N for the string at 30° to the vertical.