A stone is thrown horizontally from the top of a cliff 45 m high with a velocity of 10 m/s. How far from the base of the cliff does the stone land? [g = 10 m/s²]

First, find the time to fall: using h = ½gt², 45 = ½ × 10 × t², giving t² = 9, so t = 3 s. The horizontal distance is x = u × t = 10 × 3 = 30 m. Option A uses t = 1 s (incorrect), and option B uses t = 2 s (incorrect).