If a force of 20 N stretches a spring by 4 cm, the spring constant is
A5 N/m
B500 N/mCORRECT
C80 N/m
D0.2 N/m
JAMB UTMEPhysics
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Why the answer is B, and why the others tempt you.
k = F/x = 20/0.04 = 500 N/m. (Convert cm to m first!)
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