A simple pendulum of length 1 m has a period of approximately (g = 10 m/s²)
A1 s
B2 sCORRECT
Cπ s
D2π s
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Why the answer is B, and why the others tempt you.
T = 2π√(L/g) = 2π√(1/10) ≈ 2π × 0.316 ≈ 2 s.
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