Three 6Ω resistors in series.

## The reasoning When resistors are connected **in series** (end-to-end, like beads on a string), the total resistance is simply the **sum** of all individual resistances. The principle: **R_total = R₁ + R₂ + R₃ + ...** Here, you have three resistors, each 6Ω: **R_total = 6Ω + 6Ω + 6Ω = 18Ω** Think of it like obstacles in a single path — each resistor adds to the opposition against current flow. --- ## Why the wrong options tempt you **A) 2Ω** — This tricks students who divide instead of add (6 ÷ 3 = 2). That's the formula for **parallel** resistors of equal value, not series! **B) 6Ω** — You might think "same value means total stays the same" — but resistance **accumulates** in series. **D) 216Ω** — This comes from multiplying (6 × 6 × 6), confusing resistance with power calculations or just overthinking it. --- ## Quick takeaway **Series = Add them up; Parallel = Reciprocals dance** — for three identical resistors in series, just multiply one value by 3.