Why the answer is B, and why the others tempt you.
## The reasoning
Alkenes are hydrocarbons with **one carbon-carbon double bond** (C=C). This double bond is the key to their formula.
Start with alkanes (single bonds only): their formula is CₙH₂ₙ₊₂. For example, ethane is C₂H₆ (which is C₂H₂₍₂₎₊₂).
Now, when you introduce a double bond, you **remove two hydrogen atoms** because two carbons now share four electrons instead of two. So from CₙH₂ₙ₊₂, subtract 2H → **CₙH₂ₙ**.
Check it: Ethene (simplest alkene) = C₂H₄ (fits C₂H₂₍₂₎ ✓). Propene = C₃H₆ (fits C₃H₂₍₃₎ ✓).
## Why the wrong options tempt you
**A) CₙH₂ₙ₊₂** — This is alkanes (no double bonds), like petrol or cooking gas.
**C) CₙH₂ₙ₋₂** — This is alkynes (triple bond C≡C), like the gas in welding torches. One more degree of unsaturation means two more H atoms lost.
**D) CₙH₂ₙ₋₁** — This doesn't match any major hydrocarbon family. It's a distractor.
## Quick takeaway
**Each double bond costs you 2 hydrogens**: alkanes are CₙH₂ₙ₊₂, alkenes lose 2H → CₙH₂ₙ, alkynes lose another 2H → CₙH₂ₙ₋₂.
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