Why the answer is A, and why the others tempt you.
**The reasoning**
Methane (CH₄) is an **alkane** because it follows the general formula CₙH₂ₙ₊₂ for alkanes. Let's check: if n = 1 (one carbon), then H = 2(1) + 2 = 4 hydrogens. Perfect match!
Alkanes are hydrocarbons with **only single bonds** between carbon atoms. Look at methane's structure: one carbon connected to four hydrogens by single bonds (C–H). No double bonds, no triple bonds, no other functional groups. That's the signature of the alkane family (also called **saturated hydrocarbons** or **paraffins**).
**Why the wrong options tempt you**
- **Alkenes (B)** contain C=C double bonds and follow CₙH₂ₙ (example: ethene, C₂H₄). Methane has no double bond.
- **Alkynes (C)** have C≡C triple bonds and follow CₙH₂ₙ₋₂ (example: ethyne, C₂H₂). Methane has no triple bond.
- **Alcohols (D)** contain an –OH group (example: methanol, CH₃OH). Methane has no oxygen at all.
**Quick takeaway**
If every bond is single (C–C or C–H) and it fits CₙH₂ₙ₊₂, it's an alkane — remember: **All Single = Alkane**.
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