If two coins are tossed, what is the probability of getting two heads?

## The reasoning When you toss two coins, there are **four equally likely outcomes**: - HH (both heads) - HT (first head, second tail) - TH (first tail, second head) - TT (both tails) Only **one** of these four outcomes gives you two heads (HH). So probability = Number of favorable outcomes ÷ Total possible outcomes = **1/4** This follows the **basic probability principle**: P(event) = (ways to get what you want) ÷ (all possible ways) ## Why the wrong options tempt you **1/2 (Option B)** tricks you if you think "each coin is 1/2, so the answer must be 1/2" — but you need *both* to show heads simultaneously, which is rarer. **3/4 (Option C)** might catch you if you counted "at least one head" instead of "two heads." **1 (Option D)** would mean it's certain — clearly wrong since you could get tails! ## Quick takeaway **List all outcomes first, then count your target** — two coins give you 4 possibilities, and only 1 shows two heads, so it's always 1/4.