Simplify: (a² - b²) / (a + b).

## The reasoning This is a **factorization problem**. The numerator a² - b² is a special pattern called **difference of two squares**. The key formula to remember: **a² - b² = (a + b)(a - b)** So let's rewrite the fraction: (a² - b²) / (a + b) = [(a + b)(a - b)] / (a + b) Now, (a + b) appears in both numerator and denominator, so they cancel out (as long as a ≠ -b): = (a - b) ## Why the wrong options tempt you **Option A (a + b)**: You might think "the denominator stays", but that's backwards — we're canceling the denominator, not keeping it. **Options C & D (a²b² and a²/b²)**: These look "mathy" but come from randomly multiplying or dividing the letters without using the factorization rule. Pure distraction. ## Quick takeaway Whenever you see **a² - b²**, immediately think **(a + b)(a - b)** — it's the most tested factorization pattern in JAMB/WAEC algebra!