Three resistors of 2Ω, 3Ω and 6Ω are connected in parallel. The effective resistance is:

**The reasoning** When resistors are in **parallel**, we use the reciprocal formula: 1/R_total = 1/R₁ + 1/R₂ + 1/R₃ Let's substitute our values: 1/R_total = 1/2 + 1/3 + 1/6 Finding a common denominator (6): 1/R_total = 3/6 + 2/6 + 1/6 = 6/6 = 1 Therefore: R_total = 1/1 = **1Ω** This is the **principle of parallel resistance** — parallel resistors always give you a *smaller* total resistance than the smallest individual resistor! **Why the wrong options tempt you** - **A) 11Ω** — You added them directly (2+3+6). That's the series formula! Wrong connection type. - **B) 5.5Ω** — You found the average (11÷2). Sounds logical but parallel circuits don't work that way. - **D) 0.5Ω** — A calculation slip, maybe dividing incorrectly at the final step. **Quick takeaway** Parallel = reciprocals first, then flip back. Series = just add. And remember: parallel resistance is *always* less than the smallest resistor in the group — it opens more paths for current!